养老宝出现问题datajson parse errorr

路由器的无线设置出了问题?出现了 《Access Error: Data follows Can't get memory》》谁能给解答下?_百度知道
路由器的无线设置出了问题?出现了 《Access Error: Data follows Can't get memory》》谁能给解答下?
我有更好的答案
恢复出厂设置(有一个键长按10秒钟),然后再重新设置。
从错误提示看,路由器内存出了问题,重启下路由器试试。
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出门在外也不愁php提示Fatal error: Call to undefined function openssl_x509_parse()-常见问题-Php教程-壹聚教程网php提示Fatal error: Call to undefined function openssl_x509_parse()
在安装一个网站时提示Fatal error: Call to undefined function openssl_x509_parse函数了,而函数openssl_x509_read是一个php内置的函数哦,这个函数像curl需要组件支持哦,我们需要在php.ini中打开相关配置即可
网站提示 Fatal error: Call to
function openssl_x509_parse()& ......
打开php.ini,找到这一行 ;extension=php_openssl.dll,将前面的&;&去掉
再重启或者iis即可
再打开网站错误不提示了,为了证明是openssl.dll没开启的原因我们可以运行
$data = openssl_x509_parse(file_get_contents('/path/to/cert.crt'));
$validFrom = date('Y-m-d H:i:s', $data['validFrom_time_t']);
$validTo ) date('Y-m-d H:i:s', $data['validTo_time_t']);
echo $validFrom . & &;
echo $validTo . & &;
这函数看看是不是没有问题哦。
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jQuery.parseJSON() Invalid Character error
jQuery parsejson()无效字符的错误。
问题 (Question)
I am getting "Invalid Character Error" when parsing string to JSon but don't know the reason..
please help me out, Here is My code
var data = $.parseJSON({ "senderEmail": "", "RecieverEmail": "alll", "Message": "j", "DateAndTime": "2013"});
for (var i = 0; i & data. i++) {
console.log("--------------------");
console.log(data[i].SenderEmail);
console.log(data[i].RecieverEmail);
console.log(data[i].DateTime);
console.log(data[i].Message);
我收到“无效字符时,字符串错误”解析JSON但不知道原因。请帮助我,这是我的代码var data = $.parseJSON({ "senderEmail": "", "RecieverEmail": "alll", "Message": "j", "DateAndTime": "2013"});
for (var i = 0; i & data. i++) {
console.log("--------------------");
console.log(data[i].SenderEmail);
console.log(data[i].RecieverEmail);
console.log(data[i].DateTime);
console.log(data[i].Message);
最佳答案 (Best Answer)
First: you already have a JSON object here, jQuery.parseJSON() takes a string as input.
Second: to access data[i] properties you'll also have to pass a list of objects.
var data = $.parseJSON('[{"senderEmail": "", "ReceiverEmail": "alll", "Message": "j", "DateAndTime": "2013"}]');
for (var i = 0; i & data. i++) {
// Now you can access data[i] properties as you want...
第一:你在这里已经有一个JSON对象,jQuery.parseJSON()使用一个字符串作为输入。第二:访问data[i]您也可以通过属性的对象列表。所以:var data = $.parseJSON('[{"senderEmail": "", "ReceiverEmail": "alll", "Message": "j", "DateAndTime": "2013"}]');
for (var i = 0; i & data. i++) {
// Now you can access data[i] properties as you want...
答案 (Answer) 2
$.parseJSON('{ "senderEmail" : "", "RecieverEmail": "alll", "Message": "j", "DateAndTime": "2013" }' );
an input for $.parseJSON() must be a string not an object
试试这个:$.parseJSON('{ "senderEmail" : "", "RecieverEmail": "alll", "Message": "j", "DateAndTime": "2013" }' );
输入$.parseJSON()必须是一个字符串不是一个对象
答案 (Answer) 3
JSON is a string which is a serialized piece of data using a subset of the JS literal syntax.
In your example you are not passing a string to parseJSON, you're passing an object literal.
var data = $.parseJSON('{"senderEmail": "", "RecieverEmail": "alll", "Message": "j", "DateAndTime": "2013"}');
JSON是一个字符串,这是一个系列片利用JS文字语法的一个子集的数据。在你的例子不是你传递一个字符串parseJSON,你传递一个对象的文字。你想要的:var data = $.parseJSON('{"senderEmail": "", "RecieverEmail": "alll", "Message": "j", "DateAndTime": "2013"}');
答案 (Answer) 4
This is already an object (without quotes), and not a json string, so nothing to parse
"senderEmail": "",
"RecieverEmail": "alll",
"Message": "j",
"DateAndTime": "2013"
A json string should be something like this
'{ "senderEmail": "", "RecieverEmail": "alll", "Message": "j", "DateAndTime": "2013"}'
Notice the quotes '{...}'. This is
of looping an object and
shows how to loop an object after parsing it from a json string, see the difference.
So, if your data is already an object then you don't need to use $.parseJSON because it just convert the json string to a JavaScript object but if this is a json string '{...}' then parse it (convert the json string to an object) then you loop it. json means JavaScript Object Notation and a json string is just a JavaScript object inside a string ('{...}' and not a real Object) and to make it a real JavaScript Object we need to parse it first, unless, we can't use it as an Object.
Read more on .
这已经是一个对象(无quotes),而不是json字符串,所以没有解析{
"senderEmail": "",
"RecieverEmail": "alll",
"Message": "j",
"DateAndTime": "2013"
JSON字符串应该是这样的'{ "senderEmail": "", "RecieverEmail": "alll", "Message": "j", "DateAndTime": "2013"}'
通知quotes '{...}'。这是循环对象演示如何循环后从一个对象解析json字符串,看到的差异。所以,如果你的数据已经是一个对象,那么你不需要使用$.parseJSON因为它只是转换json字符串到JavaScript但如果这是一个对象json字符串'{...}'然后分析它(转换json字符串对象)然后你循环。json方法JavaScript Object Notation和一个json字符串只是一个JavaScript在一个字符串对象('{...}'并不是一个真正的对象),使它成为一个真正的JavaScript对象我们需要分析首先,除非,我们不能使用它作为一个Object。阅读更多关于。
答案 (Answer) 5
First of all you trying to parse JSON itself, it is not string
var data = $.parseJSON('[{ "senderEmail": "", "RecieverEmail": "alll",
"Message": "j", "DateAndTime": "2013"}]');
for (var i = 0; i & data. i++) {
console.log("--------------------");
console.log(data[i].senderEmail);
console.log(data[i].RecieverEmail);
console.log(data[i].Message);
console.log(data[i].DateAndTime);
首先你要解析JSON本身,它不是字符串var data = $.parseJSON('[{ "senderEmail": "", "RecieverEmail": "alll",
"Message": "j", "DateAndTime": "2013"}]');
for (var i = 0; i & data. i++) {
console.log("--------------------");
console.log(data[i].senderEmail);
console.log(data[i].RecieverEmail);
console.log(data[i].Message);
console.log(data[i].DateAndTime);
本文翻译自StackoverFlow,英语好的童鞋可直接参考原文:

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